Motu to Potlu house
Description
Motu decided to visit his friend Potlu. It turned out that the Motu's house is located at point 0 and his friend's house is located at point x (x > 0) of the coordinate line. In one step the Motu can move 1, 2, 3, 4 or 5 positions forward.
Determine, what is the minimum number of steps he need to make in order to get to his friend's house.
Input
Input Format :
First and the only line contain the integer n which denotes the position of his friend's house.
Constraints :
1 <= n <= 10^6
Output
Output contains a single line denoting the minimum number of steps.
Hint
Output Explanation :
For n = 26, Motu can move as
5 --> 5 --> 5 --> 5 --> 5 --> 1
Hence he needed 6 steps to reach position 26.
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int times = sc.nextInt();
if(times<5){
System.out.println(1);
}else {
if (times%5==0){
System.out.println(times/5);
}else {
System.out.println((times/5)+1);
}
}
}
}
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